我將用純python給出一個方法。

從數學模塊導入sqrt函數：

from math import sqrt

假設您在cords表中有以下坐標：

cords['Boston'] = (5, 2)

定義一個函數來計算兩個給定二維點的歐氏距離：def dist(a, b):

d = [a[0] - b[0], a[1] - b[1]]

return sqrt(d[0] * d[0] + d[1] * d[1])

將結果矩陣初始化為字典：D = {}

for city1, cords1 in cords.items():

D[city1] = {}

for city2, cords2 in cords.items():

D[city1][city2] = dist(cords1, cords2)

D是你的結果矩陣

完整的來源和打印結果如下：from math import sqrt

cords = {}

cords['Boston'] = (5, 2)

cords['Phoenix'] = (7, 3)

cords['New York'] = (8, 1)

def dist(a, b):

d = [a[0] - b[0], a[1] - b[1]]

return sqrt(d[0] * d[0] + d[1] * d[1])

D = {}

for city1, cords1 in cords.items():

D[city1] = {}

for city2, cords2 in cords.items():

D[city1][city2] = dist(cords1, cords2)

for city1, v in D.items():

for city2, d in v.items():

print city1, city2, d

結果：Boston Boston 0.0

Boston New York 3.16227766017

Boston Phoenix 2.2360679775

New York Boston 3.16227766017

New York New York 0.0

New York Phoenix 2.2360679775

Phoenix Boston 2.2360679775

Phoenix New York 2.2360679775

Phoenix Phoenix 0.0

總結

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