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Java-大集合拆分为指定大小的小集合

發布時間:2023/12/13 java 25 豆豆
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因為Oracle數據的in 最大允許1000 ,超過就會報錯, 所以需要將集合拆分為多個集合進行處理.

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/*** 拆分集合* @param <T>* @param resList 要拆分的集合* @param count 每個集合的元素個數* @return 返回拆分后的各個集合*/public static <T> List<List<T>> split(List<T> resList,int count){if(resList==null ||count<1)return null ;List<List<T>> ret=new ArrayList<List<T>>();int size=resList.size();if(size<=count){ //數據量不足count指定的大小 ret.add(resList);}else{int pre=size/count;int last=size%count;//前面pre個集合,每個大小都是count個元素for(int i=0;i<pre;i++){List<T> itemList=new ArrayList<T>();for(int j=0;j<count;j++){itemList.add(resList.get(i*count+j));}ret.add(itemList);}//last的進行處理if(last>0){List<T> itemList=new ArrayList<T>();for(int i=0;i<last;i++){itemList.add(resList.get(pre*count+i));}ret.add(itemList);}}return ret;}

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/*** @param args*/public static void main(String[] args) {// TODO Auto-generated method stubList<String> resList=Arrays.asList("0","1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26","27","28","29","30","31","32","33","34","35","36","37","38","39","40","41","42","43","44","45","46","47","48","49","50","51","52","53","54","55","56","57","58","59","60","61","62","63","64","65","66","67","68","69","70","71","72","73","74","75","76","77","78","79","80","81","82","83","84","85","86","87","88","89","90","91","92","93","94","95","96","97","98","99");List<List<String>> ret=split(resList,10);for(int i=0;i<ret.size();i++){System.out.println(ret.get(i));}}

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轉載于:https://www.cnblogs.com/yangw/p/4126225.html

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