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tic tac toe php,Python tic-tac-toe检测作弊

發(fā)布時(shí)間:2025/3/17 php 18 豆豆
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所以現(xiàn)在我寫(xiě)了一個(gè)簡(jiǎn)單的井字游戲。我甚至沒(méi)有使用我所做的所有功能,但我的問(wèn)題是:

我如何判斷玩家是否在已經(jīng)有1或2的地方放置1或2,我想我知道怎么做,但是如果他們輸入非法字符或試圖覆蓋已經(jīng)放置的1或2,我如何才能將它們放回“輸入你的號(hào)碼”提示符。在

還有沒(méi)有更緊湊的方法來(lái)實(shí)現(xiàn)這一點(diǎn)?在

游戲代碼如下:nr = [0,0,0,0,0,0,0,0,0]

keepGoing = True

def checkP1():

if nr[0] and nr[1] and nr[2] or nr[3] and nr[4] and nr[5] or nr[6] and nr[7] and nr[8] or nr[0] and nr[3] and \

nr[6] or nr[1] and nr[4] and nr[7] or nr[2] and nr[5] and nr[8] or nr[0] and nr[4] and nr[8] or nr[2] and nr[4] and nr[6] == 1:

print("P1 Wins")

keepGoing = False

return keepGoing

def checkP2():

if nr[0] and nr[1] and nr[2] or nr[3] and nr[4] and nr[5] or nr[6] and nr[7] and nr[8] or nr[0] and nr[3] and \

nr[6] or nr[1] and nr[4] and nr[7] or nr[2] and nr[5] and nr[8] or nr[0] and nr[4] and nr[8] or nr[2] and nr[4] and nr[6] == 2:

print("P2 Wins")

keepGoing = False

return keepGoing

def Game():

while keepGoing:

PrintBoard()

in1 = 0

in2 = 0

in1 = input("Please enter the number of the position you want to put your symbol P1.")

nr[int(in1)-1] = 1

check = checkP1()

if check == 0:

PrintBoard()

break

in2 = input("Please enter the number of the position you want to put your symbol P2.")

check = checkP2()

if check == 0:

PrintBoard()

break

nr[int(in2)-1] = 2

def PrintBoard():

print("",nr[0],nr[1],nr[2],"\n",nr[3],nr[4],nr[5],"\n",nr[6],nr[7],nr[8])

def Reset():

nr = [0,0,0,0,0,0,0,0,0]

keepGoing = True

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