想象這樣做的代碼并不難，問題在于它很快就會顯得雜亂無章。

如果數據集不是太大，一個方法，你可以考慮以下方法：

/* We find all gaps. the output dataset is a mapping: the data of which minute (reference_minute) do we need to create each minute of data*/

data MINUTE_MAPPING (keep=current_minute reference_minute);

set YOUR_DATA;

by min;

retain last_minute 2; *set to the first minute you have;

if _N_ NE 1 and first.min then do;

/* Find gaps, map them to the last minute of data we have*/

if last_minute+1 < min then do;

do current_minute=last_minute+1 to min-1;

reference_minute=last_minute;

output;

end;

end;

/* For the available data, we map the minute to itself*/

reference_minute=min;

current_minute=min;

output;

*update;

last_minute=min;

end;

run;

/* Now we apply our mapping to the data */

*you must use proc sql because it is a many-to-many join, data step merge would give a different outcome;

proc sql;

create table RESULT as

select YD.current_minute as min, YD.rank, YD.qty

MINUTE_MAPPING as MM

join YOUR_DATA as YD

on (MM.reference_minute=YD.min)

;

quit;

更高性能的方法將涉及與陣列掛羊頭賣狗肉。 但我覺得這種方法更有吸引力(免責聲明：一開始就想到)，之后其他人更快地掌握(免責聲明：imho)。

良好的措施，陣列方法：

data RESULT (keep=min rank qty);

set YOUR_DATA;

by min;

retain last_minute; *assume that first record really is first minute;

array last_data{5} _TEMPORARY_;

if _N_ NE 1 and first.min and last_minute+1 < min then do; *gap found;

do current_min=last_minute+1 to min-1;

*store data of current record;

curr_min=min;

curr_rank=rank;

curr_qty=qty;

*produce records from array with last available data;

do iter=1 to 5;

min = current_minute;

rank = iter;

qty = last_data{iter};

if qty NE . then output; *to prevent output of 5th element where there are only 4;

end;

*put back values of actual current record before proceeding;

min=curr_min;

rank=curr_rank;

qty=curr_qty;

end;

*update;

last_minute=min;

end;

*insert data for use on later missing minutes;

last_data{rank}=qty;

if last.min and rank<5 then last_data{5}=.;

output; *output actual current data point;

run;

希望它能幫助。 請注意，目前我無法訪問SAS客戶端。所以未經測試的代碼可能包含一些錯字。

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