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vb的GUID生成算法

發(fā)布時間:2024/4/14 编程问答 40 豆豆
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源代碼推薦:vb的GUID生成算法

'RETURNS:??GUID?if?successful;?blank?string?otherwise.?
'
Unlike?the?GUIDS?in?the?registry,?this?function?returns?GUID?
'
without?"-"?characters.??See?comments?for?how?to?modify?if?you?
'
want?the?dash.?

Public?Function?GUID()?As?String?
????
Dim?lRetVal?As?Long?
????
Dim?udtGuid?As?GUID?
?????
????
Dim?sPartOne?As?String?
????
Dim?sPartTwo?As?String?
????
Dim?sPartThree?As?String?
????
Dim?sPartFour?As?String?
????
Dim?iDataLen?As?Integer?
????
Dim?iStrLen?As?Integer?
????
Dim?iCtr?As?Integer?
????
Dim?sAns?As?String?
????
????
On?Error?GoTo?errorhandler?
????sAns?
=?""?
?????
????lRetVal?
=?CoCreateGuid(udtGuid)?
?????
????
If?lRetVal?=?0?Then?
?????
???????
'First?8?chars?
????????sPartOne?=?Hex$(udtGuid.PartOne)?
????????iStrLen?
=?Len(sPartOne)?
????????iDataLen?
=?Len(udtGuid.PartOne)?
????????sPartOne?
=?String((iDataLen?*?2)?-?iStrLen,?"0")?_?
????????
&?Trim$(sPartOne)?
?????????
????????
'Next?4?Chars?
????????sPartTwo?=?Hex$(udtGuid.PartTwo)?
????????iStrLen?
=?Len(sPartTwo)?
????????iDataLen?
=?Len(udtGuid.PartTwo)?
????????sPartTwo?
=?String((iDataLen?*?2)?-?iStrLen,?"0")?_?
????????
&?Trim$(sPartTwo)?
????????????
????????
'Next?4?Chars?
????????sPartThree?=?Hex$(udtGuid.PartThree)?
????????iStrLen?
=?Len(sPartThree)?
????????iDataLen?
=?Len(udtGuid.PartThree)?
????????sPartThree?
=?String((iDataLen?*?2)?-?iStrLen,?"0")?_?
????????
&?Trim$(sPartThree)???'Next?2?bytes?(4?hex?digits)?
????????????
????????
'Final?16?chars?
????????For?iCtr?=?0?To?7?
????????????sPartFour?
=?sPartFour?&?_?
????????????Format$(
Hex$(udtGuid.PartFour(iCtr)),?"00")?
????????
Next?

?????
'To?create?GUID?with?"-",?change?line?below?to:?
?????'sAns?=?sPartOne?&?"-"?&?sPartTwo?&?"-"?&?sPartThree?_?
?????'&?"-"?&?sPartFour?
????????
???????sAns?
=?sPartOne?&?sPartTwo?&?sPartThree?&?sPartFour?
?????????????
????????
End?If?
?????????
????????GUID?
=?sAns?
Exit?Function?


errorhandler:?
'return?a?blank?string?if?there's?an?error?
Exit?Function?
End?Function?

轉(zhuǎn)載于:https://www.cnblogs.com/todd/archive/2005/02/15/104550.html

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